b^4-9b^2+14=0

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Solution for b^4-9b^2+14=0 equation:


Simplifying
b4 + -9b2 + 14 = 0

Reorder the terms:
14 + -9b2 + b4 = 0

Solving
14 + -9b2 + b4 = 0

Solving for variable 'b'.

Factor a trinomial.
(2 + -1b2)(7 + -1b2) = 0

Subproblem 1

Set the factor '(2 + -1b2)' equal to zero and attempt to solve: Simplifying 2 + -1b2 = 0 Solving 2 + -1b2 = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b2 = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b2 = 0 + -2 -1b2 = 0 + -2 Combine like terms: 0 + -2 = -2 -1b2 = -2 Divide each side by '-1'. b2 = 2 Simplifying b2 = 2 Take the square root of each side: b = {-1.414213562, 1.414213562}

Subproblem 2

Set the factor '(7 + -1b2)' equal to zero and attempt to solve: Simplifying 7 + -1b2 = 0 Solving 7 + -1b2 = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1b2 = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1b2 = 0 + -7 -1b2 = 0 + -7 Combine like terms: 0 + -7 = -7 -1b2 = -7 Divide each side by '-1'. b2 = 7 Simplifying b2 = 7 Take the square root of each side: b = {-2.645751311, 2.645751311}

Solution

b = {-1.414213562, 1.414213562, -2.645751311, 2.645751311}

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